topic pour atteindre les 1000 pages avant fin 2005

Bon, moi faut que je mette un coup de collier avant de partir
donc je vous laisse
A+

melimelo dit:
MrGirafe dit:Et la danse orientale alors ?

j'y suis allée hier soir, c'était bien sympa, c'était un cours pour débutantes, donc plus facile :D
J'ai eu l'impression d'être bonne :wink:


si je repond a ça monsieur slim me tue
a plus
alain

félicitation la mélimelo !

L’amélie Mélo elle fait rien qu’exprès d’écrire des trucs salaces

Parce qu’elle sait que le forum est très masculin et que le mâle aime le salace

Tout comme la lôche aime la salade

Let the music play…

Let the music play…

salade

salace (c’est différent, allez voir par vous même…)

bon je prend de l’avance

C ALGORITHM 478 COLLECTED ALGORITHMS FROM ACM.
C ALGORITHM APPEARED IN COMM. ACM, VOL. 17, NO. 06,
C P. 319.
SUBROUTINE L1(M,N,M2,N2,A,B,TOLER,X,E,S) A 010
C THIS SUBROUTINE USES A MODIFICATION OF THE SIMPLEX METHOD
C OF LINEAR PROGRAMMING TO CALCULATE AN L1 SOLUTION TO AN
C OVER-DETERMINED SYSTEM OF LINEAR EQUATIONS.
C DESCRIPTION OF PARAMETERS.
C M NUMBER OF EQUATIONS.
C N NUMBER OF UNKNOWNS (M.GE.N).
C M2 SET EQUAL TO M+2 FOR ADJUSTABLE DIMENSIONS.
C N2 SET EQUAL TO N+2 FOR ADJUSTABLE DIMENSIONS.
C A TWO DIMENSIONAL REAL ARRAY OF SIZE (M2,N2).
C ON ENTRY, THE COEFFICIENTS OF THE MATRIX MUST BE
C STORED IN THE FIRST M ROWS AND N COLUMNS OF A.
C THESE VALUES ARE DESTROYED BY THE SUBROUTINE.
C B ONE DIMENSIONAL REAL ARRAY OF SIZE M. ON ENTRY, B
C MUST CONTAIN THE RIGHT HAND SIDE OF THE EQUATIONS.
C THESE VALUES ARE DESTROYED BY THE SUBROUTINE.
C TOLER A SMALL POSITIVE TOLERANCE. EMPIRICAL EVIDENCE
C SUGGESTS TOLER=10**(-D2/3) WHERE D REPRESENTS
C THE NUMBER OF DECIMAL DIGITS OF ACCURACY AVALABLE
C (SEE DESCRIPTION).
C X ONE DIMENSIONAL REAL ARRAY OF SIZE N. ON EXIT, THIS
C ARRAY CONTAINS A SOLUTION TO THE L1 PROBLEM.
C E ONE DIMENSIONAL REAL ARRAY OF SIZE M. ON EXIT, THIS
C ARRAY CONTAINS THE RESIDUALS IN THE EQUATIONS.
C S INTEGER ARRAY OF SIZE M USED FOR WORKSPACE.
C ON EXIT FROM THE SUBROUTINE, THE ARRAY A CONTAINS THE
C FOLLOWING INFORMATION.
C A(M+1,N+1) THE MINIMUM SUM OF THE ABSOLUTE VALUES OF
C THE RESIDUALS.
C A(M+1,N+2) THE RANK OF THE MATRIX OF COEFFICIENTS.
C A(M+2,N+1) EXIT CODE WITH VALUES.
C 0 - OPTIMAL SOLUTION WHICH IS PROBABLY NON-
C UNIQUE (SEE DESCRIPTION).
C 1 - UNIQUE OPTIMAL SOLUTION.
C 2 - CALCULATIONS TERMINATED PREMATURELY DUE TO
C ROUNDING ERRORS.
C A(M+2,N+2) NUMBER OF SIMPLEX ITERATIONS PERFORMED.
DOUBLE PRECISION SUM
REAL MIN, MAX, A(M2,N2), X(N), E(M), B(M)
INTEGER OUT, S(M)
LOGICAL STAGE, TEST
C BIG MUST BE SET EQUAL TO ANY VERY LARGE REAL CONSTANT.
C ITS VALUE HERE IS APPROPRIATE FOR THE IBM 370.
DATA BIG/1.E75/
C INITIALIZATION.
M1 = M + 1
N1 = N + 1
DO 10 J=1,N
A(M2,J) = J
X(J) = 0.
10 CONTINUE
DO 40 I=1,M
A(I,N2) = N + I
A(I,N1) = B(I)
IF (B(I).GE.0.) GO TO 30
DO 20 J=1,N2
A(I,J) = -A(I,J)
20 CONTINUE
30 E(I) = 0.
40 CONTINUE
C COMPUTE THE MARGINAL COSTS.
DO 60 J=1,N1
SUM = 0.D0
DO 50 I=1,M
SUM = SUM + A(I,J)
50 CONTINUE
A(M1,J) = SUM
60 CONTINUE
C STAGE I.
C DETERMINE THE VECTOR TO ENTER THE BASIS.
STAGE = .TRUE.
KOUNT = 0
KR = 1
KL = 1
70 MAX = -1.
DO 80 J=KR,N
IF (ABS(A(M2,J)).GT.N) GO TO 80
D = ABS(A(M1,J))
IF (D.LE.MAX) GO TO 80
MAX = D
IN = J
80 CONTINUE
IF (A(M1,IN).GE.0.) GO TO 100
DO 90 I=1,M2
A(I,IN) = -A(I,IN)
90 CONTINUE
C DETERMINE THE VECTOR TO LEAVE THE BASIS.
100 K = 0
DO 110 I=KL,M
D = A(I,IN)
IF (D.LE.TOLER) GO TO 110
K = K + 1
B(K) = A(I,N1)/D
S(K) = I
TEST = .TRUE.
110 CONTINUE
120 IF (K.GT.0) GO TO 130
TEST = .FALSE.
GO TO 150
130 MIN = BIG
DO 140 I=1,K
IF (B(I).GE.MIN) GO TO 140
J = I
MIN = B(I)
OUT = S(I)
140 CONTINUE
B(J) = B(K)
S(J) = S(K)
K = K - 1
C CHECK FOR LINEAR DEPENDENCE IN STAGE I.
150 IF (TEST .OR. .NOT.STAGE) GO TO 170
DO 160 I=1,M2
D = A(I,KR)
A(I,KR) = A(I,IN)
A(I,IN) = D
160 CONTINUE
KR = KR + 1
GO TO 260
170 IF (TEST) GO TO 180
A(M2,N1) = 2.
GO TO 350
180 PIVOT = A(OUT,IN)
IF (A(M1,IN)-PIVOT-PIVOT.LE.TOLER) GO TO 200
DO 190 J=KR,N1
D = A(OUT,J)
A(M1,J) = A(M1,J) - D - D
A(OUT,J) = -D
190 CONTINUE
A(OUT,N2) = -A(OUT,N2)
GO TO 120
C PIVOT ON A(OUT,IN).
200 DO 210 J=KR,N1
IF (J.EQ.IN) GO TO 210
A(OUT,J) = A(OUT,J)/PIVOT
210 CONTINUE
DO 230 I=1,M1
IF (I.EQ.OUT) GO TO 230
D = A(I,IN)
DO 220 J=KR,N1
IF (J.EQ.IN) GO TO 220
A(I,J) = A(I,J) - D
A(OUT,J)
220 CONTINUE
230 CONTINUE
DO 240 I=1,M1
IF (I.EQ.OUT) GO TO 240
A(I,IN) = -A(I,IN)/PIVOT
240 CONTINUE
A(OUT,IN) = 1./PIVOT
D = A(OUT,N2)
A(OUT,N2) = A(M2,IN)
A(M2,IN) = D
KOUNT = KOUNT + 1
IF (.NOT.STAGE) GO TO 270
C INTERCHANGE ROWS IN STAGE I.
KL = KL + 1
DO 250 J=KR,N2
D = A(OUT,J)
A(OUT,J) = A(KOUNT,J)
A(KOUNT,J) = D
250 CONTINUE
260 IF (KOUNT+KR.NE.N1) GO TO 70
C STAGE II.
STAGE = .FALSE.
C DETERMINE THE VECTOR TO ENTER THE BASIS.
270 MAX = -BIG
DO 290 J=KR,N
D = A(M1,J)
IF (D.GE.0.) GO TO 280
IF (D.GT.(-2.)) GO TO 290
D = -D - 2.
280 IF (D.LE.MAX) GO TO 290
MAX = D
IN = J
290 CONTINUE
IF (MAX.LE.TOLER) GO TO 310
IF (A(M1,IN).GT.0.) GO TO 100
DO 300 I=1,M2
A(I,IN) = -A(I,IN)
300 CONTINUE
A(M1,IN) = A(M1,IN) - 2.
GO TO 100
C PREPARE OUTPUT.
310 L = KL - 1
DO 330 I=1,L
IF (A(I,N1).GE.0.) GO TO 330
DO 320 J=KR,N2
A(I,J) = -A(I,J)
320 CONTINUE
330 CONTINUE
A(M2,N1) = 0.
IF (KR.NE.1) GO TO 350
DO 340 J=1,N
D = ABS(A(M1,J))
IF (D.LE.TOLER .OR. 2.-D.LE.TOLER) GO TO 350
340 CONTINUE
A(M2,N1) = 1.
350 DO 380 I=1,M
K = A(I,N2)
D = A(I,N1)
IF (K.GT.0) GO TO 360
K = -K
D = -D
360 IF (I.GE.KL) GO TO 370
X(K) = D
GO TO 380
370 K = K - N
E(K) = D
380 CONTINUE
A(M2,N2) = KOUNT
A(M1,N2) = N1 - KR
SUM = 0.D0
DO 390 I=KL,M
SUM = SUM + A(I,N1)
390 CONTINUE
A(M1,N1) = SUM
RETURN
END

a plus
alain

Comme ça tu fais un copier-coller une fois arrivé chez toi, c’est ça ?

C’est pas bête comme disquette… Enfin, pour les fichiers textes

Moi, je trouve le site très fluide ce soir… C’est de bonne augure pour exploser les scores

Parce que l’objectif est tout de même de 500 !! Et on en est un peu loin encore

Je veux bien croire que tout le monde se réserve pour la fin, mais tout de même…

J’ai l’impression qu’on ne sera pas au top aujourd’hui.

Cela dit, si on fait 550 d’ici dimanche soir, on est bon !!

Alors je change l’objectif : Objectif 550 avant dimanche soir

Pas mal non ? Moi, tout ce que je veux, c’est jouer au football